A beam of unpolarized light travels from a transparent liquid of...

According to Brewster's law for an interface between two media, the tangent of the polarizing angle $i_p$ is equal to the relative refractive index of the second medium with respect to the first.

$\tan(i_p) = \dfrac{\mu_2}{\mu_1}$

Given that the refractive index of the incident medium (liquid) is $\mu_1 = \sqrt{2}$ and the refracting medium (glass) is $\mu_2 = \sqrt{6}$, we have:

$\tan(i_p) = \dfrac{\sqrt{6}}{\sqrt{2}} = \sqrt{3}$

Therefore, $i_p = 60^{\circ}$.

Answer: $60^{\circ}$