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NEET
Exam
NEET
Subject
Physics
Chapter
Wave Optics

NEET · Physics · Wave Optics

Two coherent sources of light, each having an intensity I_0 ,...

Two coherent sources of light, each having an intensity I0I_0, interfere to produce a fringe pattern on a screen. At a point on the screen where the path difference between the waves is λ6\dfrac{\lambda}{6} (where λ\lambda is the wavelength of light), the resultant intensity will be

Options

  1. AI0I_0
  2. B2I02I_0
  3. C3I03I_0
  4. D4I04I_0

Correct answer

C. 3I03I_0

Step-by-step solution

The phase difference Δϕ\Delta\phi is related to the path difference Δx\Delta x by the formula:
Δϕ=2πλΔx\Delta\phi = \dfrac{2\pi}{\lambda} \Delta x

Given Δx=λ6\Delta x = \dfrac{\lambda}{6}, the phase difference is:
Δϕ=2πλ×λ6=π3\Delta\phi = \dfrac{2\pi}{\lambda} \times \dfrac{\lambda}{6} = \dfrac{\pi}{3}

The resultant intensity II for two coherent sources of equal intensity I0I_0 is given by:
I=4I0cos⁡2(Δϕ2)I = 4I_0 \cos^2\left(\dfrac{\Delta\phi}{2}\right)

Substituting Δϕ=π3\Delta\phi = \dfrac{\pi}{3}:
I=4I0cos⁡2(π6)I = 4I_0 \cos^2\left(\dfrac{\pi}{6}\right)

Since cos⁡(π6)=32\cos\left(\dfrac{\pi}{6}\right) = \dfrac{\sqrt{3}}{2}:
I=4I0(32)2=4I0×34=3I0I = 4I_0 \left(\dfrac{\sqrt{3}}{2}\right)^2 = 4I_0 \times \dfrac{3}{4} = 3I_0

Answer: 3I03I_0
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