In an interference experiment using two coherent sources of light, the phase difference between the waves arriving at a specific point on the screen is 3 . The fringe formed at this point is a

Step-by-step solution

For destructive interference (minima), the phase difference must be an odd multiple of , given by the condition = (2n-1) , where n = 1, 2, 3, represents the order of the minimum. Given the phase difference = 3 , we can equate: (2n-1) = 3 2n - 1 = 3 2n = 4 n = 2 Therefore, the fringe formed at this point is the second minimum. Answer: Second minimum