A Young's double slit apparatus produces interference fringes of width 1.2 ~mm on a screen when the experiment is performed in air. If the entire apparatus is immersed in a transparent liquid of refractive index (4)/(3)

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Correct answer: D. 0.9 ~mm

The fringe width in air is given by β = (λ D)/(d) When the entire apparatus is immersed in a liquid of refractive index μ , the wavelength of light in the liquid becomes λ' = (λ)/(μ) . The new fringe width β' is: β' = (λ' D)/(d) = (λ D)/(μ d) = (β)/(μ) Substitute the given values: β = 1.2 ~mm μ = (4)/(3) β' = (1.2)/((4)/(3)) = 1.2 × (3)/(4) = 0.9 ~mm Answer: 0.9 ~mm

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