In a modified Young's double slit experiment, the two coherent sources illuminating the slits are maintained at an initial phase difference of . What type of fringe will be observed at the geometric center of the screen?

Step-by-step solution

The total phase difference at any point on the screen is the sum of the initial phase difference between the sources and the phase difference due to the path difference. = _ initial + 2 x At the geometric center of the screen, the path difference from the two slits is zero ( x = 0 ). Given that the initial phase difference _ initial = , the total phase difference at the center is: = + 0 = A phase difference of an odd multiple of results in destructive interference. Therefore, a completely dark fringe (minimum) will