NEETPhysicsWave Optics
The critical angle for a certain transparent medium with respect to air is ⁻¹ ( 3 5 ) . The polarising angle (Brewster's angle) for light travelling from air to this medium is:
Options
- A⁻¹ ( 3 5 )
- B⁻¹ ( 5 3 )
- C⁻¹ ( 5 3 )
- D⁻¹ ( 3 5 )
Correct answer
B. ⁻¹ ( 5 3 )
Step-by-step solution
The critical angle C is related to the refractive index of the medium by the formula: (C) = 1 Given C = ⁻¹ ( 3 5 ) , we have (C) = 3 5 . Therefore, the refractive index is = 5 3 . According to Brewster's law, the polarising angle i_p is given by: (i_p) = Substituting the value of : (i_p) = 5 3 i_p = ⁻¹ ( 5 3 ) Answer: ⁻¹ ( 5 3 )