In a Young's double slit experiment, a light of wavelength 500 ~nm falls on it. Its slits separation is 2 ~mm and distance between plane of slits and screen is 2 ~m then, find distance of a point on the screen from central maxima where inte

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In a Young's double slit experiment, a light of wavelength 500 ~nm falls on it. Its slits separation is 2 ~mm and distance between plane of slits and screen is 2 ~m then, find distance of a point on the screen from central maxima where intensity becomes 50 % of central maxima.

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Correct answer: D. 125 m

aligned & I=I₀ ^2 2 = I₀ 2 & 2 = 1 2 2 = 4 , = 2 & x= 4 & y= 4 = D 4 d = 500 10⁻⁹ 2 4 2 10⁻³ =125 10⁻⁶ ~m & y=125 m aligned

In a Young's double slit experiment, a light of wavelength 500 ~nm falls on it. Its slits separation is 2 ~mm and distance between plane of slits and screen is 2 ~m then, find distance of a point on the screen from central maxima where intensity becomes 50 % of central maxima.

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