Light of wavelength 6000 Å falls on a single slit of width 0.1 ~mm . The second minima will be formed for the angle of diffraction of

Step-by-step solution

Here, wavelength =6000 Å=6000 10⁻¹⁰ ~m Slit width a=0.1 ~mm =0.1 10⁻³ ~m In case of diffraction at single slit, the position of minima is given by a _n=n , where n=1,2,3, . second minimum, n=2 a ₂=2 For small angle ₂ ₂ . ₂= 2 a Substituting the values, we get ₂= 2 6000 10⁻¹⁰ 0.1 10⁻³ =0.012 radian