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AIIMS 201827 May
Exam
AIIMS
Year
2018
Date
27 May
Subject
Physics
Chapter
Wave Optics

AIIMS 2018 · 27 May · Physics · Wave Optics

The head lights of a jeep are 1.2 ~m apart. If the pupil of the eye...

The head lights of a jeep are 1.2 m1.2 \mathrm{~m} apart. If the pupil of the eye of an observer has a diameter of 2 mm2 \mathrm{~mm} and light of wavelength 5896A˚5896 Å is used, what should be the maximum distance of the jeep from the observer if the two head lights are just separated?

Options

  1. A33.3 km33.3 \mathrm{~km}
  2. B33.3 m33.3 \mathrm{~m}
  3. C3.33 km3.33 \mathrm{~km}
  4. D3.33 m3.33 \mathrm{~m}

Correct answer

C. 3.33 km3.33 \mathrm{~km}

Step-by-step solution

Distance of jeep, x=D×d1.22×λx=\frac{D \times d}{1.22 \times \lambda} D=D= diameter of lens, d=d= separation between sources. or x=(2×10−3)×1.21.22×5896×10−10 mx=\frac{\left(2 \times 10^{-3}\right) \times 1.2}{1.22 \times 5896 \times 10^{-10}} \mathrm{~m} or x=3336 mx=3336 \mathrm{~m} or x=3.33 kmx=3.33 \mathrm{~km}.
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