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AIIMS 2015
Exam
AIIMS
Year
2015
Subject
Physics
Chapter
Wave Optics

AIIMS 2015 · Physics · Wave Optics

In a certain double slit experimental arrangement, interference...

In a certain double slit experimental arrangement, interference fringes of width 1 mm1 \mathrm{~mm} each are observed when light of wavelength 5000A˚5000 Å is used. Keeping the setup unaltered, if the source is replaced by another of wavelength 6000A˚6000 Å, the fringe width will be

Options

  1. A1.2 mm1.2 \mathrm{~mm}
  2. B0.5 mm0.5 \mathrm{~mm}
  3. C1 mm1 \mathrm{~mm}
  4. D1.5 mm1.5 \mathrm{~mm}

Correct answer

A. 1.2 mm1.2 \mathrm{~mm}

Step-by-step solution

Fringe width, β=λDd\beta=\frac{\lambda D}{d} Since DanddD and d are unaltered, β∝λ\beta \propto \lambda. ∴β′β=λ′λ or β′=β×λ′λ=1×60005000=1.2 mm\begin{aligned}& \therefore \frac{\beta^{\prime}}{\beta}=\frac{\lambda^{\prime}}{\lambda}\\ & \text{ or } \beta^{\prime}=\beta \times \frac{\lambda^{\prime}}{\lambda}=1 \times \frac{6000}{5000}=1.2 \mathrm{~mm} \end{aligned}
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