NEET2011PhysicsWave OpticsActual
In an interference, the intensity of two interfering waves are I and 4 I respectively. They produce intensity at two points A and B with phase angle of / 2 and respectively. Then difference in between them is
Options
- AI
- B2 I
- C4 I
- D5 I
Correct answer
C. 4 I
Step-by-step solution
Resultant intensity, I=I₁+I₂+2 I₁ I₂ Here, I₁=I, I₂=4 I, ₁= 2 and ₂= At A intensity, I_A=I+4 I+2 4 I^2 2 =5 I At B intensity, I_B=I+4 I+2 4 I^2 =5 I-4 I=I Therefore, difference between intensities is I_A-I_B=5 I-I=4 I