Light is incident normally on a diffraction grating through which the first diffraction is seen at (32^ ). In this case the second order diffraction will be

Step-by-step solution

Angle of first order diffraction ( ₁ )=32^ . We know that the angle of diffraction for the n th order ( _n ) is given by d _n=n . For first order diffraction we get d 32^ =1 or, =d 32^ . Now for second order diffraction, d ₂=2 or, d ₂=2 d 32^ or ₂=2 32^ =2 0.529=1.06 . Since the sine of any angle cannot be greater than 1 , therefore there is no second order diffraction.