NEETChemistrySome Basic Concepts of Chemistry
Match the column. ( array |l|l|l|l| & Column I & & Column II (A) & array l No. of g in 20 mol~ H ₂ SO ₄ array & (P) & 20 ~N _ A (B) & array l No of mol of H ₂ O in 540 ~g array & (Q) & 6.02 10¹³ (C) & array l No of atoms in 10⁻¹⁰ ~g ~H ₂ array & (R) & 30 (D) & array l No of amu in 20 ~g array & (S) & 1960 array )
Options
- A(A) ( ) (S), (B) ( ) (R), (C) ( ) (Q), (D) ( ) (P)
- B(( A ) ( P ),( B ) ( R ),( C ) ( S ),( D ) ( Q ) )
- C(( A ) ( R ),( B ) ( S ),( C ) ( P ),( D ) ( Q ) )
- D(A) ( ) (P), (B) ( ) (R), (C) ( ) (Q), (D) ( ) (S)
Correct answer
A. (A) ( ) (S), (B) ( ) (R), (C) ( ) (Q), (D) ( ) (P)
Step-by-step solution
(A) No. of (g ) in 20 mol ( H ₂ SO ₄ ) ( H ₂ SO ₄= ) Molar mass of ( Mass =20, mol 98 ) - Matches with (S). (B) No. of mol of ( H ₂ O ) in ( 5 4 0 ~ g ) ( H ₂ O =2 ) Molar mass of - Moles (= 540, ~g 18, ~g / mol = ) - Matches with (R). (C) No. of atoms in (10⁻¹⁰, ~g , H ₂ ) - Molar mass of ( H ₂= 2 ) ( aligned Moles = 10⁻¹⁰, ~g 2, ~g / mol = & 5 5 & 10⁻¹¹, ~mol 6.0 aligned ) No. of atoms = atoms - Matches with (Q). (D) No. of amu in ( 2 0 ~ g ) ( 1 ~g =1000 mg ), hence 20 g corresponds to 20 amu when converted dire