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Exam
NEET
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry

NEET · Chemistry · Some Basic Concepts of Chemistry

Match the column. ( Column I Column II (A) array l 8g-atoms of...

Match the column. (
Column IColumn II
(A)8g−atomsof</td></tr><tr><td>Hydrogen\begin{array}{l} 8g-atoms of</td></tr><tr><td>Hydrogen \end{array}(P)2moles</td></tr><tr><td>C3H4\begin{array}{l} 2 moles</td></tr><tr><td>C_3 H_4 \end{array}
(B)6g−atomsof</td></tr><tr><td>Carbon\begin{array}{l} 6 g -atoms of</td></tr><tr><td>Carbon \end{array}(Q)3moles</td></tr><tr><td>CH3COOH\begin{array}{l} 3 moles</td></tr><tr><td>CH_3 COOH \end{array}
(C)6g−atomsof</td></tr><tr><td>oxygen\begin{array}{l} 6 g -atoms of</td></tr><tr><td>oxygen \end{array}(R)4moles</td></tr><tr><td>N2H2\begin{array}{l} 4 moles</td></tr><tr><td>N_2 H_2 \end{array}
(D)4g−molecules</td></tr><tr><td>ofNitrogen\begin{array}{l} 4 g -molecules</td></tr><tr><td>of Nitrogen \end{array}(S)2moles</td></tr><tr><td>N2O3\begin{array}{l} 2 moles</td></tr><tr><td>N_2 O_3 \end{array}
)

Options

  1. A((\mathrm{A}) \rightarrow(\mathrm{P}, \mathrm{Q})(\mathrm{B}) \rightarrow(\mathrm{R}, \mathrm{S})(\mathrm{C}) \rightarrow(\mathrm{P}, \mathrm{S})(\mathrm{D}) \rightarrow(\mathrm{P}))
  2. B(A) (\rightarrow(\mathrm{P}, \mathrm{R})) (B) (\rightarrow) (P,Q) (C) (\rightarrow) (Q,S) (D) (\rightarrow) (R)
  3. C((\mathrm{A}) \rightarrow(\mathrm{P}, \mathrm{R})(\mathrm{B}) \rightarrow(\mathrm{P}, \mathrm{R})(\mathrm{C}) \rightarrow(\mathrm{R}, \mathrm{S})(\mathrm{D}) \rightarrow(\mathrm{S}))
  4. D(A) (\rightarrow(\mathrm{R}, \mathrm{S})(\mathrm{B}) \rightarrow(\mathrm{P}, \mathrm{S})(\mathrm{C}) \rightarrow(\mathrm{Q}, \mathrm{R})(\mathrm{D}) \rightarrow(\mathrm{Q}))

Correct answer

C. ((\mathrm{A}) \rightarrow(\mathrm{P}, \mathrm{R})(\mathrm{B}) \rightarrow(\mathrm{P}, \mathrm{R})(\mathrm{C}) \rightarrow(\mathrm{R}, \mathrm{S})(\mathrm{D}) \rightarrow(\mathrm{S}))

Step-by-step solution

Column I (A) (\mathrm{8}) g-atoms of Hydrogen: - Molar mass of (\mathrm{H}=1, \mathrm{ g} / \mathrm{mol}) - Moles = (\frac{8, \mathrm{ g}}{1, \mathrm{ g} / \mathrm{mol}}=8), moles of H atoms - For (\mathrm{C}_3 \mathrm{H}_4) : Each molecule has 4 H atoms, so 2 moles of (\mathrm{C}_3 \mathrm{H}_4) contain 8, II. - Matches with (P). (B) 6 g -atoms of Carbon: - Molar mass of (\mathrm{C}=12, \mathrm{ g} / \mathrm{mol}) - Moles (=\frac{6, \mathrm{ g}}{12, \mathrm{ g} / \mathrm{mol}}=0.5), moles of C - For (\mathrm{CH}_3 \mathrm{COOH}) : Each molecule has 2 C, so 3 moles have 6 C . - Matches with (Q). (C) 6 g-atoms of Oxygen: - Molar mass of (\mathrm{O}=16, \mathrm{ g} / \mathrm{mol}) (C) 6 g-atoms of Oxygen: - Molar mass of (\mathrm{O}=16, \mathrm{ g} / \mathrm{mol}) - Moles = (\frac{6, \mathrm{ g}}{16, \mathrm{ g} / \mathrm{mol}}=0.375, \text{ moles of } \mathrm{O}) - For (\mathrm{N}_2 \mathrm{O}_3) : Each molecule has 3 O , so 2 moles have 6 O. - Matches with (S). (D) (\mathrm{4}) g-molecules of Nitrogen: - Molar mass of (\mathrm{N}_{\mathrm{2}}=\mathrm{2 8}, \mathrm{g} / \mathrm{m o l}) - Moles (=\frac{4, \mathrm{ g}}{28, \mathrm{ g} / \mathrm{mol}}=\frac{1}{7}), moles of (\mathrm{N}_2). - For (\mathrm{N}_2 \mathrm{H}_2: 4 \mathrm{ g}) corresponds to 2 moles. - Matches with (R). Summary of Matches - ((A) \rightarrow(P)) - (B) (\rightarrow) (Q) - (C) (\rightarrow) (S) - (D) (\rightarrow) (R)
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