NEETChemistryStructure of Atom
Match the following ( array |l|l|l|l| & List - I & & List - II & (Complex) & & (Spin only Magnetic moment) A & [ CoF ₆ ]^ [3- & I & 0 B & [ Co ( C ₂ O ₄ )₃ ]³⁻ & II & 24 C & [ FF ₆ ]³⁻ & III & 8 D & [ Mn ( CN )₆ ]³⁻ & IV & 35 & & V & 15 array ) The correct answer is:
Options
- AA-V, B-II, C-IV, D-I
- BA-II, B-I, C-IV, D-III
- CA-II, B-I, C-V, D-III
- DA-III, B-II, C-I, D-V
Correct answer
B. A-II, B-I, C-IV, D-III
Step-by-step solution
[ CoF ₆ ]³⁻: Co is present as Co ³⁺ and F ⁻ is a weakfield ligand. Thus, Co ³⁺=[ Ar ] 3 ~d ^6 with four unpaired electrons. = n ( n +2) B.M. = 4(4+2) = 24 [ Co ( C ₂ O ₄ )₃ ]³⁻: Co is present as Co ³⁺ and C ₂ O ₄ ²⁻ is strong-field ligand. Thus, Co ³⁺=[ Ar ] 3 ~d ^6 with all paired electrons. = n ( n +2) = 0(0+2) =0 [ FeF ₆ ]³⁻: Fe is present as Fe ³⁺ and F ⁻ is a weak-field ligand. Thus, Fe ³⁺=[ Ar ] 3 ~d ^5 with five unpaired electrons. =- n ( n +2) = 5(5+2) = 35 [ Mn ( CN )₆ ]³⁻: Mn is present as Mn ³⁺ and CN ⁻