NEETChemistryStructure of Atom
Four orbitals in a multi-electron atom are described by their number of radial and angular nodes as follows: Orbital P: 2 angular nodes, 1 radial node Orbital Q: 1 angular node, 3 radial nodes Orbital R: 0 angular nodes, 5 radial nodes Orbital S: 3 angular nodes, 0 radial nodes The correct increasing order of energy of these orbitals is:
Options
- AS P Q R
- BP = S Q R
- CP Q R S
- DR Q P S
Correct answer
C. P Q R S
Step-by-step solution
The number of angular nodes is equal to the azimuthal quantum number ( l ). The number of radial nodes is given by (n - l - 1) . For Orbital P: l = 2 , radial nodes = n - 2 - 1 = 1 n = 4 . This is the 4d orbital. (n+l) = 4 + 2 = 6 . For Orbital Q: l = 1 , radial nodes = n - 1 - 1 = 3 n = 5 . This is the 5p orbital. (n+l) = 5 + 1 = 6 . For Orbital R: l = 0 , radial nodes = n - 0 - 1 = 5 n = 6 . This is the 6s orbital. (n+l) = 6 + 0 = 6 . For Orbital S: l = 3 , radial nodes = n - 3 - 1 = 0 n = 4 . This is the 4f orbi