NEETChemistryStructure of Atom
Match List-I with List-II. List-I (Ions) List-II (Spin-only magnetic moment in B.M.) (A) Fe ²⁺ (I) 1.73 (B) Mn ²⁺ (II) 2.84 (C) Ti ³⁺ (III) 4.90 (D) Ni ²⁺ (IV) 5.92 Choose the correct answer from the options given below:
Options
- A(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
- B(A)-(III), (B)-(IV), (C)-(II), (D)-(I)
- C(A)-(II), (B)-(IV), (C)-(I), (D)-(III)
- D(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
Correct answer
D. (A)-(III), (B)-(IV), (C)-(I), (D)-(II)
Step-by-step solution
The spin-only magnetic moment is calculated using the formula = n(n+2) B.M. , where n is the number of unpaired electrons. (A) Fe ²⁺ ( Z=26 ): [ Ar ] 3 d ^6 . It has 4 unpaired electrons ( n=4 ). = 4(6) = 24 4.90 B.M. (B) Mn ²⁺ ( Z=25 ): [ Ar ] 3 d ^5 . It has 5 unpaired electrons ( n=5 ). = 5(7) = 35 5.92 B.M. (C) Ti ³⁺ ( Z=22 ): [ Ar ] 3 d ^1 . It has 1 unpaired electron ( n=1 ). = 1(3) = 3 1.73 B.M. (D) Ni ²⁺ ( Z=28 ): [ Ar ] 3 d ^8 . It has 2 unpaired electrons ( n=2 ). = 2(4) = 8 2.84 B.M. Therefore, the corre