In hydrogen atom, the de-Broglie wavelength of an electron in the second Bohr orbit is [Given that, Bohr radius, a ₀=52.9 pm ]

Step-by-step solution

According to Bohr, aligned & mvr = nh 2 & 2 r = nh mv = n aligned ..(i) [ = h mv ] where, r = radius, = wavelength n = number of orbit Also, r= a₀ n^2 Z where, a ₀= Bohr radius =52.9 pm Z = atomic number On substituting the value of ' r ' from Eq. (ii) to Eq. (i), we get aligned n & = 2 n ^2 a ₀ Z = 2 na ₀ Z & =2 2 52.9 [ n =2, Z =1] & =211.6 pm aligned