A magnetic moment of 1.73 BM will be shown by one among the following

Step-by-step solution

Magneitc moment, is related with number of unpaired electrons as aligned & = n(n+2) BM (1.73)^2 & =n(n+2) aligned On solving n=1 Thus, the complex/compound having one unpaired electron exhibit a magnetic moment of 1.73 BM . (a) aligned & [ Cu ( NH ₃ )₄ ]²⁺ & Cu ²⁺=[ Ar ] 3 d^9 aligned (Although in the presence of strong field ligand NH ₃ , the unpaired electron gets excited to higher energy level but it still remains unpaired). (b) aligned & [ Nl ( CN )₄ ]²⁻ & Ni ²⁺=[ Ar ] 30^8 aligned But CN ⁻ being strong field l