What is the wave number of 4^ th line in Balmer series of hydrogen spectrum? (R=1,09,677 ~cm ⁻¹ . )

Step-by-step solution

v =R ( 1 n₁^2 - 1 n₂^2 ) For Balmer series n₁=2 and for 4^ th line in Balmer series n₂=6 aligned R & =109677 ~cm ⁻¹ v & =109677 ( 1 2^2 - 1 6^2 ) & =109677 ( 1 4 - 1 36 ) v & =24,372 ~cm ⁻¹ aligned