Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NEETChemistryRedox Reactions

To equalize the number of electrons in both half-reactions, what is the multiplication factor applied to the oxidation half-reaction?

Options

  1. A1
  2. B2
  3. C3
  4. D6

Correct answer

D. 6

Step-by-step solution

The oxidation half-reaction is multiplied by 6 to equalize the number of electrons in both half-reactions.

Practice Redox Reactions on Quantrex Academy →

More from Redox Reactions

Calculate the oxidation number of sulfur in H ₂ SO ₄ . 2026Consider the following compounds : K O ₂, H ₂ O ₂ and H ₂ S O ₄ The oxidation state of the underlined elements in them are respectively, 2026What is the oxidation number of phosphorus in Mg ₂ P ₂ O ₇ ? 2026Identify oxidant and reductant, respectively, in the following reaction: Zn (s) + Cu ²⁺(aq) Zn ²⁺(aq) + Cu (s) 2026Which of the following is true regarding oxidation? 2026In a reaction, 2 H ₂ S + SO ₂ 2 H ₂ O + 3 S Identify the substance oxidized. 2026Predict the oxidation number of of 'C' in K ₂ C ₂ O ₄ and in CH ₂ Cl ₂ . 2026The oxidation process involves 2026 Full Redox Reactions list All NEET PYQs