Choose the correct representation of conductometric titration of...

${C}_{6}{H}_{5}\mathop{C}_{\left(WA\right)}OOH + Na\mathop{O}_{\left(SB\right)}H \to {C}_{6}{H}_{5}\mathop{C}_{\left(Salt\right)}OONa + {H}_{2}O$

 Initially the conductance is low due to the feeble ionisation of acetic acid. On the addition of base, there is decrease in conductance($A \to B$) not only due to the replacement of${H}^{+}$ by ${Na}^{+}$ but also suppresses the dissociation of benzoic acid due to common ion benzoate. But very soon, the conductance increases($B \to C$) on adding $NaOH$ as $NaOH$ neutralises the un-dissociated ${C}_{6}{H}_{5}COOH$ to ${C}_{6}{H}_{5}COONa$ which is the strong electrolyte. This increase in conductance continues raise up to the equivalence point. The graph near the equivalence point is curved due the hydrolysis of salt ${C}_{6}{H}_{5}COONa$. Beyond the equivalence point, conductance increases($C \to D$) more rapidly with the addition of $NaOH$ due to the highly conducting ${OH}^{-}$ ions