NEETChemistryRedox Reactions
HCHO (l) + 2 Cu 2+ (aq) + 5 OH – (aq) → Cu 2 O(s) + HCOO – (aq) + 3H 2 O(l)
Options
- ASubstance Oxidised: HCHO Substance Reduced: Cu 2+ Oxidising Agent: Cu 2+ Reducing Agent: HCHO
- BSubstance Oxidised: Cu 2+ Substance Reduced: HCHO Oxidising Agent: HCHO Reducing Agent: Cu 2+ Correct Option:
- CSubstance Oxidised: OH – Substance Reduced: Cu 2+ Oxidising Agent: Cu 2+ Reducing Agent: OH –
- DSubstance Oxidised: Cu 2+ Substance Reduced: OH – Oxidising Agent: OH – Reducing Agent: Cu 2+
Correct answer
B. Substance Oxidised: Cu 2+ Substance Reduced: HCHO Oxidising Agent: HCHO Reducing Agent: Cu 2+ Correct Option:
Step-by-step solution
Correct Option is : (B) Substance Oxidised: Cu 2+ Substance Reduced: HCHO Oxidising Agent: HCHO Reducing Agent: Cu 2+ Correct Option: (b)