Identify the correct increasing order of the oxidation state of nitrogen in the following species.

Step-by-step solution

Let us calculate the oxidation state of nitrogen ( x ) in each species. In NH ₄^+ : x + 4(+1) = +1 x = -3 In N ₂ H ₄ : 2x + 4(+1) = 0 2x = -4 x = -2 In NO ₂^- : x + 2(-2) = -1 x - 4 = -1 x = +3 In NO ₃^- : x + 3(-2) = -1 x - 6 = -1 x = +5 The increasing order of oxidation states is -3 Hence, the correct sequence is NH ₄^+ Answer: NH ₄^+ < N ₂ H ₄ < NO ₂^- < NO ₃^-