NEETChemistryRedox Reactions
What is the change in the oxidation number of nitrogen in the following reaction? N ₂ H ₄(l) + O ₂(g) N ₂(g) + 2 H ₂ O (l)
Options
- A+2 to 0
- B0 to -2
- C-2 to +2
- D-2 to 0
Correct answer
D. -2 to 0
Step-by-step solution
In hydrazine ( N ₂ H ₄ ), let the oxidation number of nitrogen be x . The oxidation number of hydrogen is generally +1 . 2x + 4(+1) = 0 2x = -4 x = -2 In elemental nitrogen ( N ₂ ), the oxidation number of nitrogen is 0 . Therefore, the change in the oxidation number of nitrogen is from -2 to 0 . Answer: -2 to 0