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Match List-I with List-II. List-I (Compound) List-II (Average Oxidation State) (A) C₃O₂ (I) +6 (B) Br₃O₈ (II) +16/3 (C) H₂S₂O₈ (III) +8/3 (D) Fe₃O₄ (IV) +4/3 Choose the correct answer from the options given below:

Options

  1. A(A)-(III), (B)-(II), (C)-(I), (D)-(IV)
  2. B(A)-(IV), (B)-(II), (C)-(I), (D)-(III)
  3. C(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
  4. D(A)-(II), (B)-(IV), (C)-(I), (D)-(III)

Correct answer

B. (A)-(IV), (B)-(II), (C)-(I), (D)-(III)

Step-by-step solution

(A) C₃O₂ (carbon suboxide): The structure is O=C=C=C=O . The terminal carbons are at +2 and the central carbon is at 0. The average oxidation state of carbon is 2 (+2) + 1 0 3 = +4/3 . (B) Br₃O₈ (tribromooctaoxide): The terminal bromine atoms are bonded to three oxygen atoms each (+6), while the central bromine is bonded to two oxygen atoms (+4). The average oxidation state of bromine is 2 (+6) + 1 (+4) 3 = +16/3 . (C) H₂S₂O₈ (Marshall's acid): Contains one peroxide linkage ( -O-O- ). The calculation is 2(+1) + 2x

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