NEETChemistryRedox Reactions
Match List-I with List-II: List-I (Species) List-II (Oxidation state of N) (A) N ₃ H (I) +4 (B) NH ₂ OH (II) +3 (C) N ₂ O ₄ (III) -1 (D) NO ₂^- (IV) -1/3 (V) +1 Choose the correct answer from the options given below:
Options
- A(A)-(IV), (B)-(V), (C)-(I), (D)-(II)
- B(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
- C(A)-(III), (B)-(V), (C)-(I), (D)-(II)
- D(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
Correct answer
D. (A)-(IV), (B)-(III), (C)-(I), (D)-(II)
Step-by-step solution
Let the oxidation state of nitrogen be x . For N ₃ H : 3x + 1(+1) = 0 x = -1/3 For NH ₂ OH : x + 2(+1) + 1(-2) + 1(+1) = 0 x + 1 = 0 x = -1 For N ₂ O ₄ : 2x + 4(-2) = 0 2x = 8 x = +4 For NO ₂^- : x + 2(-2) = -1 x - 4 = -1 x = +3 Therefore, the correct matching is (A)-(IV), (B)-(III), (C)-(I), (D)-(II). Answer: (A)-(IV), (B)-(III), (C)-(I), (D)-(II)