In an acidic medium, 10 mL of 0.25 M oxalic acid is titrated with KMn O₄ solution. If the volume of KMnO₄ solution required to reach end point is 10 mL, the strength of the KMnO₄ solution is

Step-by-step solution

In an acidic medium, the reaction of KMn O₄ with oxalic acid involves the following changes in oxidation states: For KMnO₄ , Mn ⁷⁺ Mn ²⁺ , so the n-factor is 5 . For oxalic acid (H₂ C₂ O₄ ), C ³⁺ C ⁴⁺ , so the n-factor is 2 1 = 2 . At the equivalence point, the number of equivalents of KMnO₄ equals the number of equivalents of oxalic acid: N₁ V₁ = N₂ V₂ (M₁ n₁) V₁ = (M₂ n₂) V₂ Substituting the given values: M₁ 5 10 = 0.25 2 10 50 M₁ = 5 M₁ = 0.10 M The strength of the KMnO₄ solution is 0.10 M.