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NEET2015ChemistryRedox ReactionsActual

Assuming complete ionization, same moles of which of the following compounds will require the least amount of acidified K M n O 4 for complete oxidation?

Options

  1. AF e S O 4
  2. BF e S O 3
  3. CF e C 2 O 4
  4. DF e N O 2 2

Correct answer

A. F e S O 4

Step-by-step solution

M n O 4 - ⟶ M n 2 + ; Change in oxidation no. = 5 In option, i. F e 2 +   ⟶ F e 3 + Change in oxidation no. = 1 ii. F e 2 +   ⟶ F e 3 + Change in oxidation no. = 1 S O 3 2 - ⟶ S O 4 2 - Change in oxidation no. = 2 = 1 + 2 = 3 iii. F e 2 +   ⟶ F e 3 + Change in oxidation no. = 1 C 2 O 4 2 - ⟶ 2 C O 2 Change in oxidation no. = 2 = 1 + 2 = 3 iv. F e 2 +   ⟶ F e 3 + Change in oxidation no. = 1 2 N O 2 - ⟶ 2 N O 3 - Change in oxidation no. = 4 =

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