In which of the following compounds, nitrogen exhibits highest oxidation state?

Step-by-step solution

Let the oxidation state of nitrogen in the given compounds be (x ). (a) ( N ₂ H ₄ ) ( aligned & 2(x)+(+1) 4=0 & 2 x=-4 aligned ) So, (x=-2 ). (b) ( NH ₃ ) (x+(+1)^3=0 ) So, (x=-3 ) (c) ( N ₃ H ) ( aligned & (x) 3+(+1)=0 & 3 x=-1 aligned ) So, (x=-1 / 3 ) (d) ( NH ₂ OH ) ( aligned & x+(+1) 2+(-2)+(+1)=0 & x+2-2+1=0 & x+1=0 aligned ) So, (x=-1 ) Thus, oxidation state of nitrogen is highest in ( N ₃ H ).