10 ~g of hydrogen and 64 ~g of oxygen were filled in a steel vessel and exploded. Amount of water produced in this reaction will be -

Step-by-step solution

H ₂+1 / 2 O ₂ H ₂ O 2 ~g 16 ~g 18 ~g 10 ~g H ₂ required O ₂=80 which is not present 64 g O ₂ required 8 ~g of H ₂ and H ₂ left =2 ~g . Thus, O ₂ is the limiting reactant and H ₂ is excess reactant. Hence, H ₂ O formed from 64 of O ₂ aligned & = 18 16 64 & =72 ~g = 72 18 ~mole & =4 ~mole aligned