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In the reaction, P + Q → R + S the time taken for 75 % reaction of P is twice the time taken for 50 % reaction of P . The concentration of Q varies with reaction time as shown in the figure.The overall order of the reaction is:

Options

  1. A2
  2. B3
  3. C0
  4. D1

Correct answer

D. 1

Step-by-step solution

The reaction is: P + Q → R + S rate of the reaction = k P x Q y The concentration of Q varies with time as per the graph by the equation. Q = Q 0 - kt ​ i.e. Zero-order kinetics. ⇒ y = 0 With respect to reactant P let time taken for 50 % completion of the reaction is a . Then the time is taken for 75 % complication will be 2 a . P → t 50 % P 2 → t 75 % P 4 at t = 0 ; [ P ] 0 % = P t = t 50 % ; [ P ] 50 % = P 2 t = t 75 % ; [ P ] 75 % = P 4 As we can see, in each time interval of 'a' min the reactant concentration i

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