NEETChemistryChemical Kinetics
For a reaction, consider the plot of l n k versus 1 / T given in the figure. If the rate constant of this reaction at 400 K is 10 - 5 s - 1 , then the rate constant at 500 K is:
Options
- A10 - 4 s - 1
- B10 - 6 s - 1
- C2 x 10 - 4 s - 1
- D4 x 10 - 4 s - 1
Correct answer
A. 10 - 4 s - 1
Step-by-step solution
l n k = l n A - E a R T = l n A - 4606 1 T 1 - 1 T 2 ∴ E A R = 4606 l n k 10 - 5 = 4606 × 500 - 400 500 × 400 l n k 10 - 5 = 4606 × 1 2000 = 2.303 l n k 10 - 5 = l n 10 k = 10 - 4 s - 1