Which of the following is/are correct for the first order reaction?

Step-by-step solution

I. log ( a – x ) , where ( a – x ) is remaining concentration, decreases with passage of time. log a − x = log a − kt 2 .303 y = log a − k 2 .3030 x slope = − ve II. k = 2.303 t log 10 ⁡ a a - x log a a - x = k 2 .303 × t = y = k 2 . 303 x y = m × x Plot of log ⁡ a a - x against 't' gives straight line through origin. III. t 1 / 2 = 0.693 k ; Half-life of first order reaction does not depend on initial concentration. Thus, graph of t 1 / 2 against 'a' gives horizontal straight line.