NEETChemistryChemical Kinetics
The kinetic study of a reaction like v A P at 300 K provides the following curve, where concentration is taken in mol dm ⁻³ and time in min. Identify the correct order (n) and rate constant (k)
Options
- An=0, k=4.0 mol dm ⁻³ min ⁻¹
- Bn=1 / 2, k=2.0 mol ^ 1 / 2 dm ^ -3 / 2 min ⁻¹
- Cn=1, k=80 min ⁻¹
- Dn=2, k=16.0 dm ³ mol ⁻¹ min ⁻¹
Correct answer
D. n=2, k=16.0 dm ³ mol ⁻¹ min ⁻¹
Step-by-step solution
From the given graph Slope = ( rate )^ 1 / 2 [A] =4 rate (r)=k[A]^ n Where, k= rate constant [A]= concentration at time t (in min). n= order. According to the graph (n=2) k= rate [A]^ n =[4]²=16 Hence, n=2 and k=16.0 dm ³ mol ⁻¹ ⁻¹ and option (d) is the correct answer.