NEETChemistryChemical Kinetics
The decomposition of dimethyl ether leads to the formation of CH 4 , H 2 and CO and the reaction rate is given by Rate = k [CH 3 OCH 3 ] 3/2 .The rate of reaction is followed by increase in pressure in a closed vessel, so the rate can also be expressed in terms of the partial pressure of dimethyl ether, i.e., Rate = k (p(CH 3 OCH 3 )) 3/2 If the pressure is measured in bar and time in minutes, then what are the units
Options
- AUnit of Rate= (bar 2 min -2 ) and Unit of Rate constant=(bar −1/2 min −1 )
- BUnit of Rate= (bar min -1 ) and Unit of Rate constant=(bar −1/2 min −1 )
- CUnit of Rate= (bar min -1 ) and Unit of Rate constant=(bar −3/2 min −1 )
- DUnit of Rate= (bar 2 min -2 ) and Unit of Rate constant=(bar −3/2 min −1 )
Correct answer
B. Unit of Rate= (bar min -1 ) and Unit of Rate constant=(bar −1/2 min −1 )
Step-by-step solution
Correct Option is : (B) Unit of Rate= (bar min -1 ) and Unit of Rate constant=(bar −1/2 min −1 )