NEETChemistryChemical Kinetics
The decomposition of hydrocarbon follows the equation k = (4.5 × 10 11 s –1 ) e -28000K/T .Calculate E a .
Options
- A465.12 kJ mol -1
- B232.79 kJ mol –1
- C836.45 kJ mol -1
- D908.33 kJ mol -1
Correct answer
B. 232.79 kJ mol –1
Step-by-step solution
Correct Option is : (B) 232.79 kJ mol –1