For a first-order reaction, the rate constant is 2.303 10⁻³ s ⁻¹ . What percentage of the initial reactant will remain unreacted after 1000 s ?

Step-by-step solution

For a first-order reaction, the integrated rate equation is: k = 2.303 t [A]₀ [A]_t Substituting the given values: 2.303 10⁻³ = 2.303 1000 [A]₀ [A]_t 1 = [A]₀ [A]_t [A]₀ [A]_t = 10^1 = 10 [A]_t = [A]₀ 10 = 0.1 [A]₀ The percentage of reactant remaining is: [A]_t [A]₀ 100 = 0.1 100 = 10 % Calculating 90 % is a common mistake where the percentage of decomposed reactant is found instead of the remaining reactant. Answer: 10 %