NEETChemistryd and f Block Elements
The set of correct statements is: (i) Manganese exhibits + 7 oxidation state in its oxide. (ii) Ruthenium and Osmium exhibit + 8 oxidation in their oxides. (iii) Sc shows + 4 oxidation state which is oxidizing in nature. (iv) Cr shows oxidising nature in + 6 oxidation state.
Options
- A(ii) and (iii)
- B(i), (ii) and (iv)
- C(i) and (iii)
- D(ii), (iii) and (iv)
Correct answer
B. (i), (ii) and (iv)
Step-by-step solution
(i) The oxidation state of Mn in oxide ( Mn 2 O 7 ) is: Let us consider Mn as x . ⇒ 2 x + 7 ( - 2 ) = 0 ⇒ 2 x + ( - 14 ) = 0 ⇒ 2 x - 14 = 0 ⇒ 2 x = 14 ⇒ x = 7 (ii) The oxidation state of Ruthenium in oxide ( RuO 4 ) is: Consider Ru as x . ⇒ x + 4 ( - 2 ) = 0 ⇒ x - 8 = 0 ⇒ x = 8 The oxidation state of Osmium in oxide ( OsO 4 ) is: Consider Os as x . ⇒ x + 4 ( - 2 ) = 0 ⇒ x - 8 = 0 ⇒ x = 8 Hence, Ruthenium and Osmium has +7 oxidation state in its oxide. (iii) Sc has ns 2 ( n - 1 ) d 1 electronic configuration. It uti