Pick out the correct set of statements for HI. 1 . It reduces iodic acid to I 2 2 . It reduces H 2 S O 4 to S O 2 3 . It decolourises acidified K M n O 4 4 . It liberates I 2 with C u S O 4 solution

Step-by-step solution

Here all statements are correct here regarding HI as follows 2 K M n O 4 + 3 H 2 S O 4 + 10 H I → K 2 S O 4 + 2 M n S O 4 + 8 H 2 O + 5 I 2 H 2 S O 4 + 2 H I → S O 2 + I 2 + 2 H 2 O H I O 3 + 5 H I → 3 I 2 + 3 H 2 O 2 C u S O 4 + 4 H I → 2 C u I 2 + 2 H 2 S O 4 2 C u I 2 → C u 2 I 2 + I 2