NEETChemistryd and f Block Elements
Which is the last element in the series of the actinoids and what is the electronic configuration and possible oxidation state of this element?
Options
- ALawrencium(Lr), [Rn]5f 14 6d 1 7s 2 and +3
- BNobelium(No), [Rn]5f 14 7s 2 and +2
- CLawrencium(Lr), [Rn]5f 12 6d 1 7s 2 and +4
- DNobelium(No), [Rn]5f 14 7s 2 and +3
Correct answer
A. Lawrencium(Lr), [Rn]5f 14 6d 1 7s 2 and +3
Step-by-step solution
Correct Option is : (A) Lawrencium(Lr), [Rn]5f 14 6d 1 7s 2 and +3