NEETChemistryd and f Block Elements
When a chromite ore (A) is fused with sodium carbonate in free excess of air and the product is dissolved in water, a yellow solution of compound (B) is obtained. After treatment of this yellow solution with sulphuric acid, compound (C) can be crystallized from the solution. When compound (C) is treated with KCl, orange crystals of compound (D) crystallize out. Identify A to D and also explain the reactions.
Options
- AA]Sodium chromate (Na₂CrO₄), B] Potassium chromate (K₂CrO₄), C] Chromic acid (H₂CrO₄), D] Potassium dichromate
- BA] Chromite ore (FeCr₂O₄), B] Sodium chromate (Na₂CrO₄), C] Sodium dichromate (Na₂Cr₂O₇), D] Potassium dichrom
- CA] Potassium dichromate (K₂Cr₂O₇), B] Chromic acid (H₂CrO₄), C] Sodium chromate (Na₂CrO₄), D] Chromite ore (Fe
- DA] Chromic acid (H₂CrO₄), B] Potassium dichromate (K₂Cr₂O₇), C] Sodium chromate (Na₂CrO₄), D] Chromite ore (Fe
Correct answer
B. A] Chromite ore (FeCr₂O₄), B] Sodium chromate (Na₂CrO₄), C] Sodium dichromate (Na₂Cr₂O₇), D] Potassium dichrom
Step-by-step solution
Correct Option is : (B) A] Chromite ore (FeCr₂O₄), B] Sodium chromate (Na₂CrO₄), C] Sodium dichromate (Na₂Cr₂O₇), D] Potassium dichromate (K₂Cr₂O₇)