Which of the following transition metal ions has a calculated spin-only magnetic moment of 5.92 BM ?

Step-by-step solution

The spin-only magnetic moment is given by the formula = n(n+2) BM , where n is the number of unpaired electrons. Given = 5.92 BM , we can find n by approximating n(n+2) 5.92 . Since 35 5.916 , we have n(n+2) = 35 , which gives n = 5 unpaired electrons. Now, let us evaluate the number of unpaired electrons for each given ion: Fe ²⁺ (Atomic number 26 ): [ Ar ] 3d^6 4 unpaired electrons. Mn ²⁺ (Atomic number 25 ): [ Ar ] 3d^5 5 unpaired electrons. Cr ³⁺ (Atomic number 24 ): [ Ar ] 3d^3 3 unpaired electrons. Mn ³⁺ (Ato