Heating potassium permanganate produces a green solid (A). When an aqueous solution of (A) is treated with a dilute acid, it undergoes disproportionation to give a purple solution (B) and a brown-black precipitate (C). The oxidation states

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Heating potassium permanganate produces a green solid (A). When an aqueous solution of (A) is treated with a dilute acid, it undergoes disproportionation to give a purple solution (B) and a brown-black precipitate (C). The oxidation states of manganese in compounds (B) and (C) are respectively:

Quantrex Academy · Accepted Answer

Correct answer: C. +7 and +4

When potassium permanganate ( KMnO ₄ ) is heated, it decomposes to form potassium manganate, which is the green solid (A). 2 KMnO ₄ K ₂ MnO ₄ (A) + MnO ₂ + O ₂ In an acidic medium, the manganate ion ( MnO ₄²⁻ ) undergoes a disproportionation reaction to form the permanganate ion ( MnO ₄^- ), which gives a purple solution (B), and manganese dioxide ( MnO ₂ ), which is a brown-black precipitate (C). 3 MnO ₄²⁻ + 4 H ^+ 2 MnO ₄^- (B) + MnO ₂ (C) + 2 H ₂ O The oxidation state of manganese in the purple solution (B), whi

Heating potassium permanganate produces a green solid (A). When an aqueous solution of (A) is treated with a dilute acid, it undergoes disproportionation to give a purple solution (B) and a brown-black precipitate (C). The oxidation states of manganese in compounds (B) and (C) are respectively:

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