NEETChemistryd and f Block Elements
Match List I with List II. List I (Ion) List II (Spin-only magnetic moment) (A) Ti ³⁺ (Z = 22) (I) 0 BM (B) Co ²⁺ (Z = 27) (II) 1.73 BM (C) Gd ³⁺ (Z = 64) (III) 3.87 BM (D) Lu ³⁺ (Z = 71) (IV) 7.9 BM Choose the correct answer from the options given below:
Options
- A(A)-(II), (B)-(IV), (C)-(I), (D)-(III)
- B(A)-(II), (B)-(III), (C)-(IV), (D)-(I)
- C(A)-(III), (B)-(IV), (C)-(II), (D)-(I)
- D(A)-(II), (B)-(III), (C)-(I), (D)-(IV)
Correct answer
B. (A)-(II), (B)-(III), (C)-(IV), (D)-(I)
Step-by-step solution
The spin-only magnetic moment is calculated using the formula = n(n+2) BM , where n is the number of unpaired electrons. (A) Ti ³⁺ (Z = 22): Configuration is [ Ar ] 3 d ¹ . Number of unpaired electrons (n) = 1. = 1(1+2) = 3 1.73 BM . (B) Co ²⁺ (Z = 27): Configuration is [ Ar ] 3 d ⁷ . Number of unpaired electrons (n) = 3. = 3(3+2) = 15 3.87 BM . (C) Gd ³⁺ (Z = 64): Configuration is [ Xe ] 4 f ⁷ . Number of unpaired electrons (n) = 7. = 7(7+2) = 63 7.9 BM . (D) Lu ³⁺ (Z = 71): Configuration is [ Xe ] 4 f ¹⁴ . Number