NEETChemistryd and f Block Elements
Match List-I with List-II regarding the oxidation reactions of KMnO₄ . List-I (Reactant and Medium) List-II (Oxidised Product) (A) Iodide in acidic medium (I) Iodate (B) Iodide in faintly alkaline medium (II) Iodine (C) Thiosulphate in faintly alkaline medium (III) Carbon dioxide (D) Oxalate in acidic medium (IV) Sulphate Choose the correct answer from the options given below:
Options
- A(A)-(I), (B)-(II), (C)-(IV), (D)-(III)
- B(A)-(II), (B)-(I), (C)-(III), (D)-(IV)
- C(A)-(I), (B)-(II), (C)-(III), (D)-(IV)
- D(A)-(II), (B)-(I), (C)-(IV), (D)-(III)
Correct answer
D. (A)-(II), (B)-(I), (C)-(IV), (D)-(III)
Step-by-step solution
In acidic medium, KMnO₄ oxidises iodide ( I^- ) to iodine ( I₂ ) and oxalate ( C₂O₄²⁻ ) to carbon dioxide ( CO₂ ). In neutral or faintly alkaline medium, KMnO₄ oxidises iodide ( I^- ) to iodate ( IO₃^- ) and thiosulphate ( S₂O₃²⁻ ) to sulphate ( SO₄²⁻ ). Therefore, the correct match is (A)-(II), (B)-(I), (C)-(IV), (D)-(III). Answer: (A)-(II), (B)-(I), (C)-(IV), (D)-(III)