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Statement I Despite having aldehyde group, glucose does not give Schiff test. Statement II Glucose exists in and crystalline forms.

Options

  1. ABoth statements I and II are incorrect.
  2. BBoth statements I and II are correct.
  3. CStatement I is correct but statement II is incorrect.
  4. DStatement I is incorrect but statement II is correct.

Correct answer

B. Both statements I and II are correct.

Step-by-step solution

Glucose does not react with Schiff's reagent because the aldehyde group in glucose is not free. It is involved in the formation of hemiacetal. Glucose exists in two different crystalline anomeric forms, alpha D-glucose and beta D-glucose. Thus, statements I and II are correct.

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