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How do you explain the presence of five —OH groups in glucose molecules?

Options

  1. AGlucose reacts with hydroxylamine to form an oxime
  2. BOn oxidation with nitric acid, glucose as well as gluconic acid both yield a dicarboxylic acid, saccharic acid
  3. CGlucose gives pentaacetate derivative on acetylation with acetic anhydride. This confirms the presence of five
  4. DOn prolonged heating with HI, it forms n-hexane

Correct answer

C. Glucose gives pentaacetate derivative on acetylation with acetic anhydride. This confirms the presence of five

Step-by-step solution

Correct Option is : (C) Glucose gives pentaacetate derivative on acetylation with acetic anhydride. This confirms the presence of five —OH groups.

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