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Why does compound (A) given below not form an oxime?

Options

  1. AGlucose pentaacetate [structure A] doesn’t have a free —OH group at C 1 and so can’t be converted to the open
  2. BGlucose pentaacetate is a cyclic compound, and oxime formation occurs primarily in linear molecules.
  3. CGlucose pentaacetate is too large to participate in oxime reactions.
  4. DGlucose pentaacetate is highly stable and does not readily undergo chemical reactions.

Correct answer

A. Glucose pentaacetate [structure A] doesn’t have a free —OH group at C 1 and so can’t be converted to the open

Step-by-step solution

Correct Option is : (A) Glucose pentaacetate [structure A] doesn’t have a free —OH group at C 1 and so can’t be converted to the open chain form to give —CHO group and hence doesn’t form the oxime.

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