To confirm the presence of hydroxyl groups in its structure, one mole of open-chain D-glucose is reacted with an excess of acetic anhydride. How many moles of acetic anhydride are consumed in this reaction, and what is the name of the derivative formed?

Step-by-step solution

The open-chain structure of D-glucose contains one aldehyde group and five hydroxyl (-OH) groups. When reacted with acetic anhydride, acetylation occurs at each of the hydroxyl groups. Since there are five hydroxyl groups, one mole of glucose reacts with five moles of acetic anhydride. The product formed is glucose pentaacetate, which confirms the presence of five -OH groups attached to different carbon atoms. Answer: 5 moles, Glucose pentaacetate